4x-4y(1+y^2)=0

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Solution for 4x-4y(1+y^2)=0 equation:


Simplifying
4x + -4y(1 + y2) = 0
4x + (1 * -4y + y2 * -4y) = 0
4x + (-4y + -4y3) = 0

Solving
4x + -4y + -4y3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
4x + -4y + 4y + -4y3 = 0 + 4y

Combine like terms: -4y + 4y = 0
4x + 0 + -4y3 = 0 + 4y
4x + -4y3 = 0 + 4y
Remove the zero:
4x + -4y3 = 4y

Add '4y3' to each side of the equation.
4x + -4y3 + 4y3 = 4y + 4y3

Combine like terms: -4y3 + 4y3 = 0
4x + 0 = 4y + 4y3
4x = 4y + 4y3

Divide each side by '4'.
x = y + y3

Simplifying
x = y + y3

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